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LeetCode-2.两数相加

LeetCode-2.两数之和

给定两个非空链表来表示两个非负整数。位数按照逆序方式存储,它们的每个节点只存储单个数字。将两数相加返回一个新的链表。

你可以假设除了数字 0 之外,这两个数字都不会以零开头。

示例:

输入:(2 -> 4 -> 3) + (5 -> 6 -> 4)
输出:7 -> 0 -> 8
原因:342 + 465 = 807

英文原文:
Add Two Numbers
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Example

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Explanation: 342 + 465 = 807.

我的解答:

 1# Definition for singly-linked list.
 2# class ListNode(object):
 3#     def __init__(self, x):
 4#         self.val = x
 5#         self.next = None
 6
 7class Solution(object):
 8    def addTwoNumbers(self, l1, l2):
 9        """
10        :type l1: ListNode
11        :type l2: ListNode
12        :rtype: ListNode
13        """
14        prev=result=ListNode(None)
15        carry = 0
16        while l1 or l2 or carry:
17            if l1:
18                carry += l1.val
19                l1 = l1.next
20            
21            if l2:
22                carry +=l2.val
23                l2 = l2.next
24            
25            prev.next = ListNode(carry % 10)
26            prev = prev.next
27            carry //= 10
28        
29        return result.next

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